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-2\sqrt{3}+\sqrt{16}+2\sqrt{3}
Factor 12=2^{2}\times 3. Rewrite the square root of the product \sqrt{2^{2}\times 3} as the product of square roots \sqrt{2^{2}}\sqrt{3}. Take the square root of 2^{2}.
-2\sqrt{3}+4+2\sqrt{3}
Calculate the square root of 16 and get 4.
4
Combine -2\sqrt{3} and 2\sqrt{3} to get 0.