Solve -sqrt[3]{8}+161/4=(-2)+27^frac{1{3}}

$$- \sqrt[ 3 ] { 8 } + 16 \frac { 1 } { 4 } = ( - 2 ) + 27 ^ { \frac { 1 } { 3 } }$$

Verify

Solution Steps

Multiply both sides of the equation by 4.

$$-4\sqrt[3]{8}+16\times 4+1=-8+4\times 27^{\frac{1}{3}}$$

Calculate \sqrt[3]{8} and get 2.

$$-4\times 2+16\times 4+1=-8+4\times 27^{\frac{1}{3}}$$

Multiply -4 and 2 to get -8.

$$-8+16\times 4+1=-8+4\times 27^{\frac{1}{3}}$$

Multiply 16 and 4 to get 64.

$$-8+64+1=-8+4\times 27^{\frac{1}{3}}$$

Add -8 and 64 to get 56.

$$56+1=-8+4\times 27^{\frac{1}{3}}$$

Add 56 and 1 to get 57.

$$57=-8+4\times 27^{\frac{1}{3}}$$

Calculate 27 to the power of \frac{1}{3} and get 3.

$$57=-8+4\times 3$$

Multiply 4 and 3 to get 12.

$$57=-8+12$$

Add -8 and 12 to get 4.

$$57=4$$

Compare 57 and 4.

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