Solve -sqrt[3]{8}+161/4=-(-2)+{27}^frac{1{3}}

$$- \sqrt[ 3 ]{ 8 } +16 \frac{ 1 }{ 4 } = -(-2)+ { 27 }^{ \frac{ 1 }{ 3 } }$$

Verify

Solution Steps

Multiply both sides of the equation by 4.

$$-4\sqrt[3]{8}+16\times 4+1=-4\left(-2\right)+4\times 27^{\frac{1}{3}}$$

Calculate \sqrt[3]{8} and get 2.

$$-4\times 2+16\times 4+1=-4\left(-2\right)+4\times 27^{\frac{1}{3}}$$

Multiply -4 and 2 to get -8.

$$-8+16\times 4+1=-4\left(-2\right)+4\times 27^{\frac{1}{3}}$$

Multiply 16 and 4 to get 64.

$$-8+64+1=-4\left(-2\right)+4\times 27^{\frac{1}{3}}$$

Add -8 and 64 to get 56.

$$56+1=-4\left(-2\right)+4\times 27^{\frac{1}{3}}$$

Add 56 and 1 to get 57.

$$57=-4\left(-2\right)+4\times 27^{\frac{1}{3}}$$

Multiply -4 and -2 to get 8.

$$57=8+4\times 27^{\frac{1}{3}}$$

Calculate 27 to the power of \frac{1}{3} and get 3.

$$57=8+4\times 3$$

Multiply 4 and 3 to get 12.

$$57=8+12$$

Add 8 and 12 to get 20.

$$57=20$$

Compare 57 and 20.

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