Solve -sqrt{9}-{4^2+3[sqrt[3]{27}+4*6]-2^3}

$$- \sqrt { 9 } - \{ 4 ^ { 2 } + 3 [ \sqrt[ 3 ] { 27 } + 4 \times 6 ] - 2 ^ { 3 } \}$$

Evaluate

$$-92$$

Solution Steps

Calculate the square root of 9 and get 3.

$$-3-\left(4^{2}+3\left(\sqrt[3]{27}+4\times 6\right)-2^{3}\right)$$

Calculate 4 to the power of 2 and get 16.

$$-3-\left(16+3\left(\sqrt[3]{27}+4\times 6\right)-2^{3}\right)$$

Calculate \sqrt[3]{27} and get 3.

$$-3-\left(16+3\left(3+4\times 6\right)-2^{3}\right)$$

Multiply 4 and 6 to get 24.

$$-3-\left(16+3\left(3+24\right)-2^{3}\right)$$

Add 3 and 24 to get 27.

$$-3-\left(16+3\times 27-2^{3}\right)$$

Multiply 3 and 27 to get 81.

$$-3-\left(16+81-2^{3}\right)$$

Add 16 and 81 to get 97.

$$-3-\left(97-2^{3}\right)$$

Calculate 2 to the power of 3 and get 8.

$$-3-\left(97-8\right)$$

Subtract 8 from 97 to get 89.

$$-3-89$$

Subtract 89 from -3 to get -92.

$$-92$$

Factor

$$-92$$