Solve -sqrt{9}+6div2+4-2^2+3*10div5-sqrt{4}-3

$$- \sqrt { 9 } + 6 \div 2 + 4 - 2 ^ { 2 } + 3 \cdot 10 \div 5 - \sqrt { 4 } - 3$$

Evaluate

$$1$$

Solution Steps

Calculate the square root of 9 and get 3.

$$-3+\frac{6}{2}+4-2^{2}+\frac{3\times 10}{5}-\sqrt{4}-3$$

Divide 6 by 2 to get 3.

$$-3+3+4-2^{2}+\frac{3\times 10}{5}-\sqrt{4}-3$$

Add -3 and 3 to get 0.

$$4-2^{2}+\frac{3\times 10}{5}-\sqrt{4}-3$$

Calculate 2 to the power of 2 and get 4.

$$4-4+\frac{3\times 10}{5}-\sqrt{4}-3$$

Subtract 4 from 4 to get 0.

$$0+\frac{3\times 10}{5}-\sqrt{4}-3$$

Multiply 3 and 10 to get 30.

$$0+\frac{30}{5}-\sqrt{4}-3$$

Divide 30 by 5 to get 6.

$$0+6-\sqrt{4}-3$$

Add 0 and 6 to get 6.

$$6-\sqrt{4}-3$$

Calculate the square root of 4 and get 2.

$$6-2-3$$

Subtract 2 from 6 to get 4.

$$4-3$$

Subtract 3 from 4 to get 1.

$$1$$

Factor

$$1$$