Solve -sqrt{36}+sqrt{12}+sqrt{8}

$$- \sqrt { 36 } + \sqrt { 12 } + \sqrt { 8 }$$

Evaluate

$$2\left(\sqrt{2}+\sqrt{3}-3\right)\approx 0.29252874$$

Solution Steps

Calculate the square root of 36 and get 6.

$$-6+\sqrt{12}+\sqrt{8}$$

Factor 12=2^{2}\times 3. Rewrite the square root of the product \sqrt{2^{2}\times 3} as the product of square roots \sqrt{2^{2}}\sqrt{3}. Take the square root of 2^{2}.

$$-6+2\sqrt{3}+\sqrt{8}$$

Factor 8=2^{2}\times 2. Rewrite the square root of the product \sqrt{2^{2}\times 2} as the product of square roots \sqrt{2^{2}}\sqrt{2}. Take the square root of 2^{2}.

$$-6+2\sqrt{3}+2\sqrt{2}$$