Solve -sqrt{36}+sqrt{12}+sqrt{3}

$$- \sqrt { 36 } + \sqrt { 12 } + \sqrt { 3 }$$

Evaluate

$$3\sqrt{3}-6\approx -0.803847577$$

Solution Steps

Calculate the square root of 36 and get 6.

$$-6+\sqrt{12}+\sqrt{3}$$

Factor 12=2^{2}\times 3. Rewrite the square root of the product \sqrt{2^{2}\times 3} as the product of square roots \sqrt{2^{2}}\sqrt{3}. Take the square root of 2^{2}.

$$-6+2\sqrt{3}+\sqrt{3}$$

Combine 2\sqrt{3} and \sqrt{3} to get 3\sqrt{3}.

$$-6+3\sqrt{3}$$