Solve -sqrt{3}6*3/3+2*(12-9)^2

$$- \sqrt { 3 } 6 \times 3 / 3 + 2 \times ( 12 - 9 ) ^ { 2 }$$

Evaluate

$$18-6\sqrt{3}\approx 7.607695155$$

Solution Steps

Divide 3 by 3 to get 1.

$$6\left(-\sqrt{3}\right)\times 1+2\left(12-9\right)^{2}$$

Multiply 6 and 1 to get 6.

$$6\left(-\sqrt{3}\right)+2\left(12-9\right)^{2}$$

Subtract 9 from 12 to get 3.

$$6\left(-\sqrt{3}\right)+2\times 3^{2}$$

Calculate 3 to the power of 2 and get 9.

$$6\left(-\sqrt{3}\right)+2\times 9$$

Multiply 2 and 9 to get 18.

$$6\left(-\sqrt{3}\right)+18$$

Multiply 6 and -1 to get -6.

$$-6\sqrt{3}+18$$

Factor

$$6 \sqrt{3} {(\sqrt{3} - 1)} = 7.607695155$$