Solve -sqrt{2}x+2y=-8-5

$$- \sqrt { 2 } x + 2 y = - 8 - 5$$

Solve for x

$$x=\frac{\sqrt{2}\left(2y+13\right)}{2}$$

Steps for Solving Linear Equation

Subtract 5 from -8 to get -13.

$$\left(-\sqrt{2}\right)x+2y=-13$$

Subtract 2y from both sides.

$$\left(-\sqrt{2}\right)x=-13-2y$$

Reorder the terms.

$$-\sqrt{2}x=-2y-13$$

The equation is in standard form.

$$\left(-\sqrt{2}\right)x=-2y-13$$

Divide both sides by -\sqrt{2}.

$$\frac{\left(-\sqrt{2}\right)x}{-\sqrt{2}}=\frac{-2y-13}{-\sqrt{2}}$$

Dividing by -\sqrt{2} undoes the multiplication by -\sqrt{2}.

$$x=\frac{-2y-13}{-\sqrt{2}}$$

Divide -2y-13 by -\sqrt{2}.

$$x=\frac{\sqrt{2}\left(2y+13\right)}{2}$$

Solve for y

$$y=\frac{\sqrt{2}x-13}{2}$$

Steps for Solving Linear Equation

Subtract 5 from -8 to get -13.

$$\left(-\sqrt{2}\right)x+2y=-13$$

Subtract \left(-\sqrt{2}\right)x from both sides.

$$2y=-13-\left(-\sqrt{2}\right)x$$

Multiply -1 and -1 to get 1.

$$2y=-13+\sqrt{2}x$$

The equation is in standard form.

$$2y=\sqrt{2}x-13$$

Divide both sides by 2.

$$\frac{2y}{2}=\frac{\sqrt{2}x-13}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$y=\frac{\sqrt{2}x-13}{2}$$