Solve -sqrt{16}+sqrt{25}-(8-9)^4-2^2=

$$- \sqrt { 16 } + \sqrt { 25 } - ( 8 - 9 ) ^ { 4 } - 2 ^ { 2 } =$$

Evaluate

$$-4$$

Solution Steps

Calculate the square root of 16 and get 4.

$$-4+\sqrt{25}-\left(8-9\right)^{4}-2^{2}$$

Calculate the square root of 25 and get 5.

$$-4+5-\left(8-9\right)^{4}-2^{2}$$

Add -4 and 5 to get 1.

$$1-\left(8-9\right)^{4}-2^{2}$$

Subtract 9 from 8 to get -1.

$$1-\left(-1\right)^{4}-2^{2}$$

Calculate -1 to the power of 4 and get 1.

$$1-1-2^{2}$$

Subtract 1 from 1 to get 0.

$$0-2^{2}$$

Calculate 2 to the power of 2 and get 4.

$$0-4$$

Subtract 4 from 0 to get -4.

$$-4$$

Factor

$$-4$$