Solve -lceil-5-9-(-1-6+9)-2+3rceil-7

$$- \lceil -5-9-(-1-6+9)-2+3 \rceil -7$$

Evaluate

$$8$$

Solution Steps

Subtract 9 from -5 to get -14.

$$-\lceil -14-\left(-1-6+9\right)-2+3\rceil -7$$

Subtract 6 from -1 to get -7.

$$-\lceil -14-\left(-7+9\right)-2+3\rceil -7$$

Add -7 and 9 to get 2.

$$-\lceil -14-2-2+3\rceil -7$$

Subtract 2 from -14 to get -16.

$$-\lceil -16-2+3\rceil -7$$

Subtract 2 from -16 to get -18.

$$-\lceil -18+3\rceil -7$$

Add -18 and 3 to get -15.

$$-\lceil -15\rceil -7$$

The ceiling of a real number a is the smallest integer number greater than or equal to a. The ceiling of -15 is -15.

$$-\left(-15\right)-7$$

The opposite of -15 is 15.

$$15-7$$

Subtract 7 from 15 to get 8.

$$8$$

Factor

$$2^{3}$$