Solve -gamma+10r-19q=0

$$- \gamma + 10 r - 19 q = 0$$

Solve for q

$$q=\frac{10r-\gamma }{19}$$

Steps for Solving Linear Equation

Add \gamma to both sides. Anything plus zero gives itself.

$$10r-19q=\gamma$$

Subtract 10r from both sides.

$$-19q=\gamma -10r$$

Divide both sides by -19.

$$\frac{-19q}{-19}=\frac{\gamma -10r}{-19}$$

Dividing by -19 undoes the multiplication by -19.

$$q=\frac{\gamma -10r}{-19}$$

Divide \gamma -10r by -19.

$$q=\frac{10r-\gamma }{19}$$

Solve for r

$$r=\frac{19q+\gamma }{10}$$

Steps for Solving Linear Equation

Add \gamma to both sides. Anything plus zero gives itself.

$$10r-19q=\gamma$$

Add 19q to both sides.

$$10r=\gamma +19q$$

The equation is in standard form.

$$10r=19q+\gamma$$

Divide both sides by 10.

$$\frac{10r}{10}=\frac{19q+\gamma }{10}$$

Dividing by 10 undoes the multiplication by 10.

$$r=\frac{19q+\gamma }{10}$$