Solve -9/40*2^2+9/10*2

$$- \frac{ 9 }{ 40 } \times { 2 }^{ 2 } + \frac{ 9 }{ 10 } \times 2$$

Evaluate

$$\frac{9}{10}=0.9$$

Solution Steps

Calculate 2 to the power of 2 and get 4.

$$-\frac{9}{40}\times 4+\frac{9}{10}\times 2$$

Express -\frac{9}{40}\times 4 as a single fraction.

$$\frac{-9\times 4}{40}+\frac{9}{10}\times 2$$

Multiply -9 and 4 to get -36.

$$\frac{-36}{40}+\frac{9}{10}\times 2$$

Reduce the fraction \frac{-36}{40} to lowest terms by extracting and canceling out 4.

$$-\frac{9}{10}+\frac{9}{10}\times 2$$

Express \frac{9}{10}\times 2 as a single fraction.

$$-\frac{9}{10}+\frac{9\times 2}{10}$$

Multiply 9 and 2 to get 18.

$$-\frac{9}{10}+\frac{18}{10}$$

Since -\frac{9}{10} and \frac{18}{10} have the same denominator, add them by adding their numerators.

$$\frac{-9+18}{10}$$

Add -9 and 18 to get 9.

$$\frac{9}{10}$$

Factor

$$\frac{3 ^ {2}}{2 \cdot 5} = 0.9$$