Solve -7/6x+-7/6+3

$$- \frac{ 7 }{ 6 } x+- \frac{ 7 }{ 6 } +3$$

Evaluate

$$\frac{11-7x}{6}$$

Solution Steps

Convert 3 to fraction \frac{18}{6}.

$$-\frac{7}{6}x-\frac{7}{6}+\frac{18}{6}$$

Since -\frac{7}{6} and \frac{18}{6} have the same denominator, add them by adding their numerators.

$$-\frac{7}{6}x+\frac{-7+18}{6}$$

Add -7 and 18 to get 11.

$$-\frac{7}{6}x+\frac{11}{6}$$

Factor

$$\frac{11-7x}{6}$$

Solution Steps

Factor out \frac{1}{6}.

$$\frac{-7x+11}{6}$$

Consider -7x-7+18. Multiply and combine like terms.

$$-7x+11$$

Rewrite the complete factored expression.

$$\frac{-7x+11}{6}$$