Solve -5/4-1/1-3/8+3/10

$$- \frac{ 5 }{ 4 } - \frac{ 1 }{ 1 } - \frac{ 3 }{ 8 } + \frac{ 3 }{ 10 }$$

Evaluate

$$-\frac{93}{40}=-2.325$$

Solution Steps

Divide 1 by 1 to get 1.

$$-\frac{5}{4}-1-\frac{3}{8}+\frac{3}{10}$$

Convert 1 to fraction \frac{4}{4}.

$$-\frac{5}{4}-\frac{4}{4}-\frac{3}{8}+\frac{3}{10}$$

Since -\frac{5}{4} and \frac{4}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-5-4}{4}-\frac{3}{8}+\frac{3}{10}$$

Subtract 4 from -5 to get -9.

$$-\frac{9}{4}-\frac{3}{8}+\frac{3}{10}$$

Least common multiple of 4 and 8 is 8. Convert -\frac{9}{4} and \frac{3}{8} to fractions with denominator 8.

$$-\frac{18}{8}-\frac{3}{8}+\frac{3}{10}$$

Since -\frac{18}{8} and \frac{3}{8} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-18-3}{8}+\frac{3}{10}$$

Subtract 3 from -18 to get -21.

$$-\frac{21}{8}+\frac{3}{10}$$

Least common multiple of 8 and 10 is 40. Convert -\frac{21}{8} and \frac{3}{10} to fractions with denominator 40.

$$-\frac{105}{40}+\frac{12}{40}$$

Since -\frac{105}{40} and \frac{12}{40} have the same denominator, add them by adding their numerators.

$$\frac{-105+12}{40}$$

Add -105 and 12 to get -93.

$$-\frac{93}{40}$$

Factor

$$-\frac{93}{40} = -2\frac{13}{40} = -2.325$$