Solve -4/3div(-1+7/9)

$$- \frac{ 4 }{ 3 } \div (-1+ \frac{ 7 }{ 9 } )$$

Evaluate

$$6$$

Solution Steps

Convert -1 to fraction -\frac{9}{9}.

$$\frac{-\frac{4}{3}}{-\frac{9}{9}+\frac{7}{9}}$$

Since -\frac{9}{9} and \frac{7}{9} have the same denominator, add them by adding their numerators.

$$\frac{-\frac{4}{3}}{\frac{-9+7}{9}}$$

Add -9 and 7 to get -2.

$$\frac{-\frac{4}{3}}{-\frac{2}{9}}$$

Divide -\frac{4}{3} by -\frac{2}{9} by multiplying -\frac{4}{3} by the reciprocal of -\frac{2}{9}.

$$-\frac{4}{3}\left(-\frac{9}{2}\right)$$

Multiply -\frac{4}{3} times -\frac{9}{2} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-4\left(-9\right)}{3\times 2}$$

Do the multiplications in the fraction \frac{-4\left(-9\right)}{3\times 2}.

$$\frac{36}{6}$$

Divide 36 by 6 to get 6.

$$6$$

Factor

$$2\times 3$$