Solve -3/4*1+3/2+6

$$- \frac{ 3 }{ 4 } \times 1+ \frac{ 3 }{ 2 } +6$$

Evaluate

$$\frac{27}{4}=6.75$$

Solution Steps

Multiply -\frac{3}{4} and 1 to get -\frac{3}{4}.

$$-\frac{3}{4}+\frac{3}{2}+6$$

Least common multiple of 4 and 2 is 4. Convert -\frac{3}{4} and \frac{3}{2} to fractions with denominator 4.

$$-\frac{3}{4}+\frac{6}{4}+6$$

Since -\frac{3}{4} and \frac{6}{4} have the same denominator, add them by adding their numerators.

$$\frac{-3+6}{4}+6$$

Add -3 and 6 to get 3.

$$\frac{3}{4}+6$$

Convert 6 to fraction \frac{24}{4}.

$$\frac{3}{4}+\frac{24}{4}$$

Since \frac{3}{4} and \frac{24}{4} have the same denominator, add them by adding their numerators.

$$\frac{3+24}{4}$$

Add 3 and 24 to get 27.

$$\frac{27}{4}$$

Factor

$$\frac{3 ^ {3}}{2 ^ {2}} = 6\frac{3}{4} = 6.75$$