Solve -25/3x+100/3=2x+2

$$- \frac{ 25 }{ 3 } x+ \frac{ 100 }{ 3 } =2x+2$$

Solve for x

$$x = \frac{94}{31} = 3\frac{1}{31} \approx 3.032258065$$

Steps for Solving Linear Equation

Subtract 2x from both sides.

$$-\frac{25}{3}x+\frac{100}{3}-2x=2$$

Combine -\frac{25}{3}x and -2x to get -\frac{31}{3}x.

$$-\frac{31}{3}x+\frac{100}{3}=2$$

Subtract \frac{100}{3} from both sides.

$$-\frac{31}{3}x=2-\frac{100}{3}$$

Convert 2 to fraction \frac{6}{3}.

$$-\frac{31}{3}x=\frac{6}{3}-\frac{100}{3}$$

Since \frac{6}{3} and \frac{100}{3} have the same denominator, subtract them by subtracting their numerators.

$$-\frac{31}{3}x=\frac{6-100}{3}$$

Subtract 100 from 6 to get -94.

$$-\frac{31}{3}x=-\frac{94}{3}$$

Multiply both sides by -\frac{3}{31}, the reciprocal of -\frac{31}{3}.

$$x=-\frac{94}{3}\left(-\frac{3}{31}\right)$$

Multiply -\frac{94}{3} times -\frac{3}{31} by multiplying numerator times numerator and denominator times denominator.

$$x=\frac{-94\left(-3\right)}{3\times 31}$$

Do the multiplications in the fraction \frac{-94\left(-3\right)}{3\times 31}.

$$x=\frac{282}{93}$$

Reduce the fraction \frac{282}{93} to lowest terms by extracting and canceling out 3.

$$x=\frac{94}{31}$$