Solve -2/3*9/14+-23/42

$$- \frac{ 2 }{ 3 } \times \frac{ 9 }{ 14 } +- \frac{ 23 }{ 42 }$$

Evaluate

$$-\frac{41}{42}\approx -0.976190476$$

Solution Steps

Multiply -\frac{2}{3} times \frac{9}{14} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-2\times 9}{3\times 14}-\frac{23}{42}$$

Do the multiplications in the fraction \frac{-2\times 9}{3\times 14}.

$$\frac{-18}{42}-\frac{23}{42}$$

Reduce the fraction \frac{-18}{42} to lowest terms by extracting and canceling out 6.

$$-\frac{3}{7}-\frac{23}{42}$$

Least common multiple of 7 and 42 is 42. Convert -\frac{3}{7} and \frac{23}{42} to fractions with denominator 42.

$$-\frac{18}{42}-\frac{23}{42}$$

Since -\frac{18}{42} and \frac{23}{42} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-18-23}{42}$$

Subtract 23 from -18 to get -41.

$$-\frac{41}{42}$$

Factor

$$-\frac{41}{42} = -0.9761904761904762$$