Solve -16/x-x+10=4-x

$$- \frac{ 16 }{ x } -x+10=4-x$$

Solve for x

$$x = \frac{8}{3} = 2\frac{2}{3} \approx 2.666666667$$

Steps for Solving Linear Equation

Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by x.

$$-16-xx+x\times 10=x\times 4-xx$$

Multiply x and x to get x^{2}.

$$-16-x^{2}+x\times 10=x\times 4-xx$$

Multiply x and x to get x^{2}.

$$-16-x^{2}+x\times 10=x\times 4-x^{2}$$

Subtract x\times 4 from both sides.

$$-16-x^{2}+x\times 10-x\times 4=-x^{2}$$

Combine x\times 10 and -x\times 4 to get 6x.

$$-16-x^{2}+6x=-x^{2}$$

Add x^{2} to both sides.

$$-16-x^{2}+6x+x^{2}=0$$

Combine -x^{2} and x^{2} to get 0.

$$-16+6x=0$$

Add 16 to both sides. Anything plus zero gives itself.

$$6x=16$$

Divide both sides by 6.

$$x=\frac{16}{6}$$

Reduce the fraction \frac{16}{6} to lowest terms by extracting and canceling out 2.

$$x=\frac{8}{3}$$