Solve -1/3=-1/9-3+b

$$- \frac{ 1 }{ 3 } = - \frac{ 1 }{ 9 } -3+b$$

Solve for b

$$b = \frac{25}{9} = 2\frac{7}{9} \approx 2.777777778$$

Steps for Solving Linear Equation

Convert 3 to fraction \frac{27}{9}.

$$-\frac{1}{3}=-\frac{1}{9}-\frac{27}{9}+b$$

Since -\frac{1}{9} and \frac{27}{9} have the same denominator, subtract them by subtracting their numerators.

$$-\frac{1}{3}=\frac{-1-27}{9}+b$$

Subtract 27 from -1 to get -28.

$$-\frac{1}{3}=-\frac{28}{9}+b$$

Swap sides so that all variable terms are on the left hand side.

$$-\frac{28}{9}+b=-\frac{1}{3}$$

Add \frac{28}{9} to both sides.

$$b=-\frac{1}{3}+\frac{28}{9}$$

Least common multiple of 3 and 9 is 9. Convert -\frac{1}{3} and \frac{28}{9} to fractions with denominator 9.

$$b=-\frac{3}{9}+\frac{28}{9}$$

Since -\frac{3}{9} and \frac{28}{9} have the same denominator, add them by adding their numerators.

$$b=\frac{-3+28}{9}$$

Add -3 and 28 to get 25.

$$b=\frac{25}{9}$$