Solve -1/2+2-3+sqrt{9}

$$- \frac{ 1 }{ 2 } +2-3+ \sqrt{ 9 }$$

Evaluate

$$\frac{3}{2}=1.5$$

Solution Steps

Convert 2 to fraction \frac{4}{2}.

$$-\frac{1}{2}+\frac{4}{2}-3+\sqrt{9}$$

Since -\frac{1}{2} and \frac{4}{2} have the same denominator, add them by adding their numerators.

$$\frac{-1+4}{2}-3+\sqrt{9}$$

Add -1 and 4 to get 3.

$$\frac{3}{2}-3+\sqrt{9}$$

Convert 3 to fraction \frac{6}{2}.

$$\frac{3}{2}-\frac{6}{2}+\sqrt{9}$$

Since \frac{3}{2} and \frac{6}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{3-6}{2}+\sqrt{9}$$

Subtract 6 from 3 to get -3.

$$-\frac{3}{2}+\sqrt{9}$$

Calculate the square root of 9 and get 3.

$$-\frac{3}{2}+3$$

Convert 3 to fraction \frac{6}{2}.

$$-\frac{3}{2}+\frac{6}{2}$$

Since -\frac{3}{2} and \frac{6}{2} have the same denominator, add them by adding their numerators.

$$\frac{-3+6}{2}$$

Add -3 and 6 to get 3.

$$\frac{3}{2}$$

Factor

$$\frac{3}{2} = 1\frac{1}{2} = 1.5$$