Solve -1/10left(0-1right)left(0+3right)left(0-3right)^2

$$- \frac{ 1 }{ 10 } \left( 0-1 \right) \left( 0+3 \right) { \left(0-3 \right) }^{ 2 }$$

Evaluate

$$\frac{27}{10}=2.7$$

Solution Steps

Subtract 1 from 0 to get -1.

$$-\frac{1}{10}\left(-1\right)\times 3\left(-3\right)^{2}$$

Multiply -\frac{1}{10} and -1 to get \frac{1}{10}.

$$\frac{1}{10}\left(0+3\right)\left(0-3\right)^{2}$$

Add 0 and 3 to get 3.

$$\frac{1}{10}\times 3\left(0-3\right)^{2}$$

Multiply \frac{1}{10} and 3 to get \frac{3}{10}.

$$\frac{3}{10}\left(0-3\right)^{2}$$

Subtract 3 from 0 to get -3.

$$\frac{3}{10}\left(-3\right)^{2}$$

Calculate -3 to the power of 2 and get 9.

$$\frac{3}{10}\times 9$$

Multiply \frac{3}{10} and 9 to get \frac{27}{10}.

$$\frac{27}{10}$$

Factor

$$\frac{3 ^ {3}}{2 \cdot 5} = 2\frac{7}{10} = 2.7$$