Solve -3^3/3-23^2-9+1/3-2*1-1

$$- \frac{ { 3 }^{ 3 } }{ 3 } -2 { 3 }^{ 2 } -9+ \frac{ 1 }{ 3 } -2 \cdot 1-1$$

Evaluate

$$-\frac{116}{3}\approx -38.666666667$$

Solution Steps

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent. Subtract 1 from 3 to get 2.

$$-3^{2}-2\times 3^{2}-9+\frac{1}{3}-2\times 1-1$$

Calculate 3 to the power of 2 and get 9.

$$-9-2\times 3^{2}-9+\frac{1}{3}-2\times 1-1$$

Calculate 3 to the power of 2 and get 9.

$$-9-2\times 9-9+\frac{1}{3}-2\times 1-1$$

Multiply 2 and 9 to get 18.

$$-9-18-9+\frac{1}{3}-2\times 1-1$$

Subtract 18 from -9 to get -27.

$$-27-9+\frac{1}{3}-2\times 1-1$$

Subtract 9 from -27 to get -36.

$$-36+\frac{1}{3}-2\times 1-1$$

Convert -36 to fraction -\frac{108}{3}.

$$-\frac{108}{3}+\frac{1}{3}-2\times 1-1$$

Since -\frac{108}{3} and \frac{1}{3} have the same denominator, add them by adding their numerators.

$$\frac{-108+1}{3}-2\times 1-1$$

Add -108 and 1 to get -107.

$$-\frac{107}{3}-2\times 1-1$$

Multiply 2 and 1 to get 2.

$$-\frac{107}{3}-2-1$$

Convert 2 to fraction \frac{6}{3}.

$$-\frac{107}{3}-\frac{6}{3}-1$$

Since -\frac{107}{3} and \frac{6}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-107-6}{3}-1$$

Subtract 6 from -107 to get -113.

$$-\frac{113}{3}-1$$

Convert 1 to fraction \frac{3}{3}.

$$-\frac{113}{3}-\frac{3}{3}$$

Since -\frac{113}{3} and \frac{3}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-113-3}{3}$$

Subtract 3 from -113 to get -116.

$$-\frac{116}{3}$$

Factor

$$-\frac{116}{3} = -38\frac{2}{3} = -38.666666666666664$$