Solve -20^3/6+20(20)+12000

$$- \frac{ { 20 }^{ 3 } }{ 6 } +20(20)+12000$$

Evaluate

$$\frac{33200}{3}\approx 11066.666666667$$

Solution Steps

Calculate 20 to the power of 3 and get 8000.

$$-\frac{8000}{6}+20\times 20+12000$$

Reduce the fraction \frac{8000}{6} to lowest terms by extracting and canceling out 2.

$$-\frac{4000}{3}+20\times 20+12000$$

Multiply 20 and 20 to get 400.

$$-\frac{4000}{3}+400+12000$$

Convert 400 to fraction \frac{1200}{3}.

$$-\frac{4000}{3}+\frac{1200}{3}+12000$$

Since -\frac{4000}{3} and \frac{1200}{3} have the same denominator, add them by adding their numerators.

$$\frac{-4000+1200}{3}+12000$$

Add -4000 and 1200 to get -2800.

$$-\frac{2800}{3}+12000$$

Convert 12000 to fraction \frac{36000}{3}.

$$-\frac{2800}{3}+\frac{36000}{3}$$

Since -\frac{2800}{3} and \frac{36000}{3} have the same denominator, add them by adding their numerators.

$$\frac{-2800+36000}{3}$$

Add -2800 and 36000 to get 33200.

$$\frac{33200}{3}$$

Factor

$$\frac{2 ^ {4} \cdot 5 ^ {2} \cdot 83}{3} = 11066\frac{2}{3} = 11066.666666666666$$