Solve -1^3/6+20(1)+12000

$$- \frac{ { 1 }^{ 3 } }{ 6 } +20(1)+12000$$

Evaluate

$$\frac{72119}{6}\approx 12019.833333333$$

Solution Steps

Calculate 1 to the power of 3 and get 1.

$$-\frac{1}{6}+20\times 1+12000$$

Multiply 20 and 1 to get 20.

$$-\frac{1}{6}+20+12000$$

Convert 20 to fraction \frac{120}{6}.

$$-\frac{1}{6}+\frac{120}{6}+12000$$

Since -\frac{1}{6} and \frac{120}{6} have the same denominator, add them by adding their numerators.

$$\frac{-1+120}{6}+12000$$

Add -1 and 120 to get 119.

$$\frac{119}{6}+12000$$

Convert 12000 to fraction \frac{72000}{6}.

$$\frac{119}{6}+\frac{72000}{6}$$

Since \frac{119}{6} and \frac{72000}{6} have the same denominator, add them by adding their numerators.

$$\frac{119+72000}{6}$$

Add 119 and 72000 to get 72119.

$$\frac{72119}{6}$$

Factor

$$\frac{41 \cdot 1759}{2 \cdot 3} = 12019\frac{5}{6} = 12019.833333333334$$