Solve -9/2+4/3*5/2+3/8:3=

$$- \frac { 9 } { 2 } + \frac { 4 } { 3 } \times \frac { 5 } { 2 } + \frac { 3 } { 8 } : 3 =$$

Evaluate

$$-\frac{25}{24}\approx -1.041666667$$

Solution Steps

Multiply \frac{4}{3} times \frac{5}{2} by multiplying numerator times numerator and denominator times denominator.

$$-\frac{9}{2}+\frac{4\times 5}{3\times 2}+\frac{\frac{3}{8}}{3}$$

Do the multiplications in the fraction \frac{4\times 5}{3\times 2}.

$$-\frac{9}{2}+\frac{20}{6}+\frac{\frac{3}{8}}{3}$$

Reduce the fraction \frac{20}{6} to lowest terms by extracting and canceling out 2.

$$-\frac{9}{2}+\frac{10}{3}+\frac{\frac{3}{8}}{3}$$

Least common multiple of 2 and 3 is 6. Convert -\frac{9}{2} and \frac{10}{3} to fractions with denominator 6.

$$-\frac{27}{6}+\frac{20}{6}+\frac{\frac{3}{8}}{3}$$

Since -\frac{27}{6} and \frac{20}{6} have the same denominator, add them by adding their numerators.

$$\frac{-27+20}{6}+\frac{\frac{3}{8}}{3}$$

Add -27 and 20 to get -7.

$$-\frac{7}{6}+\frac{\frac{3}{8}}{3}$$

Express \frac{\frac{3}{8}}{3} as a single fraction.

$$-\frac{7}{6}+\frac{3}{8\times 3}$$

Cancel out 3 in both numerator and denominator.

$$-\frac{7}{6}+\frac{1}{8}$$

Least common multiple of 6 and 8 is 24. Convert -\frac{7}{6} and \frac{1}{8} to fractions with denominator 24.

$$-\frac{28}{24}+\frac{3}{24}$$

Since -\frac{28}{24} and \frac{3}{24} have the same denominator, add them by adding their numerators.

$$\frac{-28+3}{24}$$

Add -28 and 3 to get -25.

$$-\frac{25}{24}$$

Factor

$$-\frac{25}{24} = -1\frac{1}{24} = -1.0416666666666667$$