Solve -8/9*(-27/32)+23/28*(-49/46)

$$- \frac { 8 } { 9 } \cdot ( - \frac { 27 } { 32 } ) + \frac { 23 } { 28 } \cdot ( - \frac { 49 } { 46 } )$$

Evaluate

$$-\frac{1}{8}=-0.125$$

Solution Steps

Multiply -\frac{8}{9} times -\frac{27}{32} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-8\left(-27\right)}{9\times 32}+\frac{23}{28}\left(-\frac{49}{46}\right)$$

Do the multiplications in the fraction \frac{-8\left(-27\right)}{9\times 32}.

$$\frac{216}{288}+\frac{23}{28}\left(-\frac{49}{46}\right)$$

Reduce the fraction \frac{216}{288} to lowest terms by extracting and canceling out 72.

$$\frac{3}{4}+\frac{23}{28}\left(-\frac{49}{46}\right)$$

Multiply \frac{23}{28} times -\frac{49}{46} by multiplying numerator times numerator and denominator times denominator.

$$\frac{3}{4}+\frac{23\left(-49\right)}{28\times 46}$$

Do the multiplications in the fraction \frac{23\left(-49\right)}{28\times 46}.

$$\frac{3}{4}+\frac{-1127}{1288}$$

Reduce the fraction \frac{-1127}{1288} to lowest terms by extracting and canceling out 161.

$$\frac{3}{4}-\frac{7}{8}$$

Least common multiple of 4 and 8 is 8. Convert \frac{3}{4} and \frac{7}{8} to fractions with denominator 8.

$$\frac{6}{8}-\frac{7}{8}$$

Since \frac{6}{8} and \frac{7}{8} have the same denominator, subtract them by subtracting their numerators.

$$\frac{6-7}{8}$$

Subtract 7 from 6 to get -1.

$$-\frac{1}{8}$$

Factor

$$-\frac{1}{8} = -0.125$$