Solve -8/3xleq6

$$- \frac { 8 } { 3 } x \leq 6$$

Solve for x

$$x\geq -\frac{9}{4}$$

Solution Steps

Multiply both sides by -\frac{3}{8}, the reciprocal of -\frac{8}{3}. Since -\frac{8}{3} is negative, the inequality direction is changed.

$$x\geq 6\left(-\frac{3}{8}\right)$$

Express 6\left(-\frac{3}{8}\right) as a single fraction.

$$x\geq \frac{6\left(-3\right)}{8}$$

Multiply 6 and -3 to get -18.

$$x\geq \frac{-18}{8}$$

Reduce the fraction \frac{-18}{8} to lowest terms by extracting and canceling out 2.

$$x\geq -\frac{9}{4}$$