Solve -8/3xleq-26/3

$$- \frac { 8 } { 3 } x \leq - \frac { 26 } { 3 }$$

Solve for x

$$x\geq \frac{13}{4}$$

Solution Steps

Multiply both sides by -\frac{3}{8}, the reciprocal of -\frac{8}{3}. Since -\frac{8}{3} is negative, the inequality direction is changed.

$$x\geq -\frac{26}{3}\left(-\frac{3}{8}\right)$$

Multiply -\frac{26}{3} times -\frac{3}{8} by multiplying numerator times numerator and denominator times denominator.

$$x\geq \frac{-26\left(-3\right)}{3\times 8}$$

Do the multiplications in the fraction \frac{-26\left(-3\right)}{3\times 8}.

$$x\geq \frac{78}{24}$$

Reduce the fraction \frac{78}{24} to lowest terms by extracting and canceling out 6.

$$x\geq \frac{13}{4}$$