Solve for x
x = \frac{2630}{357} = 7\frac{131}{357} \approx 7.366946779
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-\frac{56}{21}+\frac{5}{2}x+\frac{57}{21}+\frac{13}{5}x=\frac{118}{3}-\frac{12}{7}
Least common multiple of 3 and 7 is 21. Convert -\frac{8}{3} and \frac{19}{7} to fractions with denominator 21.
\frac{-56+57}{21}+\frac{5}{2}x+\frac{13}{5}x=\frac{118}{3}-\frac{12}{7}
Since -\frac{56}{21} and \frac{57}{21} have the same denominator, add them by adding their numerators.
\frac{1}{21}+\frac{5}{2}x+\frac{13}{5}x=\frac{118}{3}-\frac{12}{7}
Add -56 and 57 to get 1.
\frac{1}{21}+\frac{51}{10}x=\frac{118}{3}-\frac{12}{7}
Combine \frac{5}{2}x and \frac{13}{5}x to get \frac{51}{10}x.
\frac{1}{21}+\frac{51}{10}x=\frac{826}{21}-\frac{36}{21}
Least common multiple of 3 and 7 is 21. Convert \frac{118}{3} and \frac{12}{7} to fractions with denominator 21.
\frac{1}{21}+\frac{51}{10}x=\frac{826-36}{21}
Since \frac{826}{21} and \frac{36}{21} have the same denominator, subtract them by subtracting their numerators.
\frac{1}{21}+\frac{51}{10}x=\frac{790}{21}
Subtract 36 from 826 to get 790.
\frac{51}{10}x=\frac{790}{21}-\frac{1}{21}
Subtract \frac{1}{21} from both sides.
\frac{51}{10}x=\frac{790-1}{21}
Since \frac{790}{21} and \frac{1}{21} have the same denominator, subtract them by subtracting their numerators.
\frac{51}{10}x=\frac{789}{21}
Subtract 1 from 790 to get 789.
\frac{51}{10}x=\frac{263}{7}
Reduce the fraction \frac{789}{21} to lowest terms by extracting and canceling out 3.
x=\frac{263}{7}\times \frac{10}{51}
Multiply both sides by \frac{10}{51}, the reciprocal of \frac{51}{10}.
x=\frac{263\times 10}{7\times 51}
Multiply \frac{263}{7} times \frac{10}{51} by multiplying numerator times numerator and denominator times denominator.
x=\frac{2630}{357}
Do the multiplications in the fraction \frac{263\times 10}{7\times 51}.
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