Solve -7/9+4/3*1/2

$$- \frac { 7 } { 9 } + \frac { 4 } { 3 } \cdot \frac { 1 } { 2 }$$

Evaluate

$$-\frac{1}{9}\approx -0.111111111$$

Solution Steps

Multiply \frac{4}{3} times \frac{1}{2} by multiplying numerator times numerator and denominator times denominator.

$$-\frac{7}{9}+\frac{4\times 1}{3\times 2}$$

Do the multiplications in the fraction \frac{4\times 1}{3\times 2}.

$$-\frac{7}{9}+\frac{4}{6}$$

Reduce the fraction \frac{4}{6} to lowest terms by extracting and canceling out 2.

$$-\frac{7}{9}+\frac{2}{3}$$

Least common multiple of 9 and 3 is 9. Convert -\frac{7}{9} and \frac{2}{3} to fractions with denominator 9.

$$-\frac{7}{9}+\frac{6}{9}$$

Since -\frac{7}{9} and \frac{6}{9} have the same denominator, add them by adding their numerators.

$$\frac{-7+6}{9}$$

Add -7 and 6 to get -1.

$$-\frac{1}{9}$$

Factor

$$-\frac{1}{9} = -0.1111111111111111$$