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-\frac{7}{4}v+\frac{5}{2}+6v=-\frac{2}{3}
Add 6v to both sides.
\frac{17}{4}v+\frac{5}{2}=-\frac{2}{3}
Combine -\frac{7}{4}v and 6v to get \frac{17}{4}v.
\frac{17}{4}v=-\frac{2}{3}-\frac{5}{2}
Subtract \frac{5}{2} from both sides.
\frac{17}{4}v=-\frac{4}{6}-\frac{15}{6}
Least common multiple of 3 and 2 is 6. Convert -\frac{2}{3} and \frac{5}{2} to fractions with denominator 6.
\frac{17}{4}v=\frac{-4-15}{6}
Since -\frac{4}{6} and \frac{15}{6} have the same denominator, subtract them by subtracting their numerators.
\frac{17}{4}v=-\frac{19}{6}
Subtract 15 from -4 to get -19.
v=-\frac{19}{6}\times \frac{4}{17}
Multiply both sides by \frac{4}{17}, the reciprocal of \frac{17}{4}.
v=\frac{-19\times 4}{6\times 17}
Multiply -\frac{19}{6} times \frac{4}{17} by multiplying numerator times numerator and denominator times denominator.
v=\frac{-76}{102}
Do the multiplications in the fraction \frac{-19\times 4}{6\times 17}.
v=-\frac{38}{51}
Reduce the fraction \frac{-76}{102} to lowest terms by extracting and canceling out 2.