Solve -7/3+[(-4)*5/3]-2=

$$- \frac { 7 } { 3 } + [ ( - 4 ) \cdot \frac { 5 } { 3 } ] - 2 =$$

Evaluate

$$-11$$

Solution Steps

Express -4\times \frac{5}{3} as a single fraction.

$$-\frac{7}{3}+\frac{-4\times 5}{3}-2$$

Multiply -4 and 5 to get -20.

$$-\frac{7}{3}+\frac{-20}{3}-2$$

Fraction \frac{-20}{3} can be rewritten as -\frac{20}{3} by extracting the negative sign.

$$-\frac{7}{3}-\frac{20}{3}-2$$

Since -\frac{7}{3} and \frac{20}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-7-20}{3}-2$$

Subtract 20 from -7 to get -27.

$$\frac{-27}{3}-2$$

Divide -27 by 3 to get -9.

$$-9-2$$

Subtract 2 from -9 to get -11.

$$-11$$

Factor

$$-11$$