Solve -7/2=3/8x-3

$$- \frac { 7 } { 2 } = \frac { 3 } { 8 } x - 3$$

Solve for x

$$x = -\frac{4}{3} = -1\frac{1}{3} \approx -1.333333333$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$\frac{3}{8}x-3=-\frac{7}{2}$$

Add 3 to both sides.

$$\frac{3}{8}x=-\frac{7}{2}+3$$

Convert 3 to fraction \frac{6}{2}.

$$\frac{3}{8}x=-\frac{7}{2}+\frac{6}{2}$$

Since -\frac{7}{2} and \frac{6}{2} have the same denominator, add them by adding their numerators.

$$\frac{3}{8}x=\frac{-7+6}{2}$$

Add -7 and 6 to get -1.

$$\frac{3}{8}x=-\frac{1}{2}$$

Multiply both sides by \frac{8}{3}, the reciprocal of \frac{3}{8}.

$$x=-\frac{1}{2}\times \frac{8}{3}$$

Multiply -\frac{1}{2} times \frac{8}{3} by multiplying numerator times numerator and denominator times denominator.

$$x=\frac{-8}{2\times 3}$$

Do the multiplications in the fraction \frac{-8}{2\times 3}.

$$x=\frac{-8}{6}$$

Reduce the fraction \frac{-8}{6} to lowest terms by extracting and canceling out 2.

$$x=-\frac{4}{3}$$