Solve -7/18-(1-1/3)^2-(-1/4-7/12)

$$- \frac { 7 } { 18 } - ( 1 - \frac { 1 } { 3 } ) ^ { 2 } - ( - \frac { 1 } { 4 } - \frac { 7 } { 12 } )$$

Evaluate

$$0$$

Solution Steps

Subtract \frac{1}{3} from 1 to get \frac{2}{3}.

$$-\frac{7}{18}-\left(\frac{2}{3}\right)^{2}-\left(-\frac{1}{4}-\frac{7}{12}\right)$$

Calculate \frac{2}{3} to the power of 2 and get \frac{4}{9}.

$$-\frac{7}{18}-\frac{4}{9}-\left(-\frac{1}{4}-\frac{7}{12}\right)$$

Subtract \frac{4}{9} from -\frac{7}{18} to get -\frac{5}{6}.

$$-\frac{5}{6}-\left(-\frac{1}{4}-\frac{7}{12}\right)$$

Subtract \frac{7}{12} from -\frac{1}{4} to get -\frac{5}{6}.

$$-\frac{5}{6}-\left(-\frac{5}{6}\right)$$

The opposite of -\frac{5}{6} is \frac{5}{6}.

$$-\frac{5}{6}+\frac{5}{6}$$

Add -\frac{5}{6} and \frac{5}{6} to get 0.

$$0$$

Factor

$$0$$