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\frac{3}{4}x-\frac{4}{3}=-\frac{5}{2}
Swap sides so that all variable terms are on the left hand side.
\frac{3}{4}x=-\frac{5}{2}+\frac{4}{3}
Add \frac{4}{3} to both sides.
\frac{3}{4}x=-\frac{15}{6}+\frac{8}{6}
Least common multiple of 2 and 3 is 6. Convert -\frac{5}{2} and \frac{4}{3} to fractions with denominator 6.
\frac{3}{4}x=\frac{-15+8}{6}
Since -\frac{15}{6} and \frac{8}{6} have the same denominator, add them by adding their numerators.
\frac{3}{4}x=-\frac{7}{6}
Add -15 and 8 to get -7.
x=-\frac{7}{6}\times \frac{4}{3}
Multiply both sides by \frac{4}{3}, the reciprocal of \frac{3}{4}.
x=\frac{-7\times 4}{6\times 3}
Multiply -\frac{7}{6} times \frac{4}{3} by multiplying numerator times numerator and denominator times denominator.
x=\frac{-28}{18}
Do the multiplications in the fraction \frac{-7\times 4}{6\times 3}.
x=-\frac{14}{9}
Reduce the fraction \frac{-28}{18} to lowest terms by extracting and canceling out 2.