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-\frac{\left(5+3\sqrt{3}\right)\left(1+\sqrt{3}\right)}{\left(1-\sqrt{3}\right)\left(1+\sqrt{3}\right)}
Rationalize the denominator of \frac{5+3\sqrt{3}}{1-\sqrt{3}} by multiplying numerator and denominator by 1+\sqrt{3}.
-\frac{\left(5+3\sqrt{3}\right)\left(1+\sqrt{3}\right)}{1^{2}-\left(\sqrt{3}\right)^{2}}
Consider \left(1-\sqrt{3}\right)\left(1+\sqrt{3}\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
-\frac{\left(5+3\sqrt{3}\right)\left(1+\sqrt{3}\right)}{1-3}
Square 1. Square \sqrt{3}.
-\frac{\left(5+3\sqrt{3}\right)\left(1+\sqrt{3}\right)}{-2}
Subtract 3 from 1 to get -2.
-\frac{5+5\sqrt{3}+3\sqrt{3}+3\left(\sqrt{3}\right)^{2}}{-2}
Apply the distributive property by multiplying each term of 5+3\sqrt{3} by each term of 1+\sqrt{3}.
-\frac{5+8\sqrt{3}+3\left(\sqrt{3}\right)^{2}}{-2}
Combine 5\sqrt{3} and 3\sqrt{3} to get 8\sqrt{3}.
-\frac{5+8\sqrt{3}+3\times 3}{-2}
The square of \sqrt{3} is 3.
-\frac{5+8\sqrt{3}+9}{-2}
Multiply 3 and 3 to get 9.
-\frac{14+8\sqrt{3}}{-2}
Add 5 and 9 to get 14.
-\left(-7-4\sqrt{3}\right)
Divide each term of 14+8\sqrt{3} by -2 to get -7-4\sqrt{3}.
-\left(-7\right)-\left(-4\sqrt{3}\right)
To find the opposite of -7-4\sqrt{3}, find the opposite of each term.
7-\left(-4\sqrt{3}\right)
The opposite of -7 is 7.
7+4\sqrt{3}
The opposite of -4\sqrt{3} is 4\sqrt{3}.