Solve -4/7n+1/3=4/21

$$- \frac { 4 } { 7 } n + \frac { 1 } { 3 } = \frac { 4 } { 21 }$$

Solve for n

$$n=\frac{1}{4}=0.25$$

Steps for Solving Linear Equation

Subtract \frac{1}{3} from both sides.

$$-\frac{4}{7}n=\frac{4}{21}-\frac{1}{3}$$

Least common multiple of 21 and 3 is 21. Convert \frac{4}{21} and \frac{1}{3} to fractions with denominator 21.

$$-\frac{4}{7}n=\frac{4}{21}-\frac{7}{21}$$

Since \frac{4}{21} and \frac{7}{21} have the same denominator, subtract them by subtracting their numerators.

$$-\frac{4}{7}n=\frac{4-7}{21}$$

Subtract 7 from 4 to get -3.

$$-\frac{4}{7}n=\frac{-3}{21}$$

Reduce the fraction \frac{-3}{21} to lowest terms by extracting and canceling out 3.

$$-\frac{4}{7}n=-\frac{1}{7}$$

Multiply both sides by -\frac{7}{4}, the reciprocal of -\frac{4}{7}.

$$n=-\frac{1}{7}\left(-\frac{7}{4}\right)$$

Multiply -\frac{1}{7} times -\frac{7}{4} by multiplying numerator times numerator and denominator times denominator.

$$n=\frac{-\left(-7\right)}{7\times 4}$$

Do the multiplications in the fraction \frac{-\left(-7\right)}{7\times 4}.

$$n=\frac{7}{28}$$

Reduce the fraction \frac{7}{28} to lowest terms by extracting and canceling out 7.

$$n=\frac{1}{4}$$