Solve -4/3x+5y=20

$$- \frac { 4 } { 3 } x + 5 y = 20$$

Solve for x

$$x=\frac{15\left(y-4\right)}{4}$$

Steps for Solving Linear Equation

Subtract 5y from both sides.

$$-\frac{4}{3}x=20-5y$$

Divide both sides of the equation by -\frac{4}{3}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{-\frac{4}{3}x}{-\frac{4}{3}}=\frac{20-5y}{-\frac{4}{3}}$$

Dividing by -\frac{4}{3} undoes the multiplication by -\frac{4}{3}.

$$x=\frac{20-5y}{-\frac{4}{3}}$$

Divide 20-5y by -\frac{4}{3} by multiplying 20-5y by the reciprocal of -\frac{4}{3}.

$$x=\frac{15y}{4}-15$$

Solve for y

$$y=\frac{4\left(x+15\right)}{15}$$

Steps for Solving Linear Equation

Add \frac{4}{3}x to both sides.

$$5y=20+\frac{4}{3}x$$

The equation is in standard form.

$$5y=\frac{4x}{3}+20$$

Divide both sides by 5.

$$\frac{5y}{5}=\frac{\frac{4x}{3}+20}{5}$$

Dividing by 5 undoes the multiplication by 5.

$$y=\frac{\frac{4x}{3}+20}{5}$$

Divide 20+\frac{4x}{3} by 5.

$$y=\frac{4x}{15}+4$$