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-\frac{4}{3}u+1+\frac{5}{2}u=-\frac{5}{3}
Add \frac{5}{2}u to both sides.
\frac{7}{6}u+1=-\frac{5}{3}
Combine -\frac{4}{3}u and \frac{5}{2}u to get \frac{7}{6}u.
\frac{7}{6}u=-\frac{5}{3}-1
Subtract 1 from both sides.
\frac{7}{6}u=-\frac{5}{3}-\frac{3}{3}
Convert 1 to fraction \frac{3}{3}.
\frac{7}{6}u=\frac{-5-3}{3}
Since -\frac{5}{3} and \frac{3}{3} have the same denominator, subtract them by subtracting their numerators.
\frac{7}{6}u=-\frac{8}{3}
Subtract 3 from -5 to get -8.
u=-\frac{8}{3}\times \frac{6}{7}
Multiply both sides by \frac{6}{7}, the reciprocal of \frac{7}{6}.
u=\frac{-8\times 6}{3\times 7}
Multiply -\frac{8}{3} times \frac{6}{7} by multiplying numerator times numerator and denominator times denominator.
u=\frac{-48}{21}
Do the multiplications in the fraction \frac{-8\times 6}{3\times 7}.
u=-\frac{16}{7}
Reduce the fraction \frac{-48}{21} to lowest terms by extracting and canceling out 3.