Solve -frac{35a^{2}b}{11a^{2}b^{2}}*-55a^4b^2/7a^3b^2

$$- \frac { 35 a ^ { 2 } b } { 11 a ^ { 2 } b ^ { 2 } } \cdot - \frac { 55 a ^ { 4 } b ^ { 2 } } { 7 a ^ { 3 } b ^ { 2 } }$$

Evaluate

$$\frac{25a}{b}$$

Solution Steps

Cancel out ba^{2} in both numerator and denominator.

$$\left(-\frac{35}{11b}\right)\left(-\frac{55a^{4}b^{2}}{7a^{3}b^{2}}\right)$$

Cancel out b^{2}a^{3} in both numerator and denominator.

$$\left(-\frac{35}{11b}\right)\left(-\frac{55a}{7}\right)$$

Multiply -\frac{35}{11b} times -\frac{55a}{7} by multiplying numerator times numerator and denominator times denominator.

$$\frac{35\times 55a}{11b\times 7}$$

Cancel out 7\times 11 in both numerator and denominator.

$$\frac{5\times 5a}{b}$$

Multiply 5 and 5 to get 25.

$$\frac{25a}{b}$$

Differentiate w.r.t. b

$$-\frac{25a}{b^{2}}$$