Skip to main content
Solve for k
Tick mark Image

Similar Problems from Web Search

Share

-3k\times 3k+k\left(9k-5\right)=6\left(11k+8\right)
Variable k cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 6k, the least common multiple of 2,6,k.
-\left(3k\right)^{2}+k\left(9k-5\right)=6\left(11k+8\right)
Multiply 3k and 3k to get \left(3k\right)^{2}.
-3^{2}k^{2}+k\left(9k-5\right)=6\left(11k+8\right)
Expand \left(3k\right)^{2}.
-9k^{2}+k\left(9k-5\right)=6\left(11k+8\right)
Calculate 3 to the power of 2 and get 9.
-9k^{2}+9k^{2}-5k=6\left(11k+8\right)
Use the distributive property to multiply k by 9k-5.
-9k^{2}+9k^{2}-5k=66k+48
Use the distributive property to multiply 6 by 11k+8.
-9k^{2}+9k^{2}-5k-66k=48
Subtract 66k from both sides.
-9k^{2}+9k^{2}-71k=48
Combine -5k and -66k to get -71k.
-71k=48
Combine -9k^{2} and 9k^{2} to get 0.
k=\frac{48}{-71}
Divide both sides by -71.
k=-\frac{48}{71}
Fraction \frac{48}{-71} can be rewritten as -\frac{48}{71} by extracting the negative sign.