Solve -3/t^4+2t^3+8/t^3

$$- \frac { 3 } { t ^ { 4 } } + 2 t ^ { 3 } + \frac { 8 } { t ^ { 3 } }$$

Evaluate

$$\frac{2t^{7}+8t-3}{t^{4}}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply 2t^{3} times \frac{t^{4}}{t^{4}}.

$$-\frac{3}{t^{4}}+\frac{2t^{3}t^{4}}{t^{4}}+\frac{8}{t^{3}}$$

Since -\frac{3}{t^{4}} and \frac{2t^{3}t^{4}}{t^{4}} have the same denominator, add them by adding their numerators.

$$\frac{-3+2t^{3}t^{4}}{t^{4}}+\frac{8}{t^{3}}$$

Do the multiplications in -3+2t^{3}t^{4}.

$$\frac{-3+2t^{7}}{t^{4}}+\frac{8}{t^{3}}$$

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of t^{4} and t^{3} is t^{4}. Multiply \frac{8}{t^{3}} times \frac{t}{t}.

$$\frac{-3+2t^{7}}{t^{4}}+\frac{8t}{t^{4}}$$

Since \frac{-3+2t^{7}}{t^{4}} and \frac{8t}{t^{4}} have the same denominator, add them by adding their numerators.

$$\frac{-3+2t^{7}+8t}{t^{4}}$$

Factor

$$\frac{2t^{7}+8t-3}{t^{4}}$$