Solve -3/5y+3leq-3

$$- \frac { 3 } { 5 } y + 3 \leq - 3$$

Solve for y

$$y\geq 10$$

Solution Steps

Subtract 3 from both sides.

$$-\frac{3}{5}y\leq -3-3$$

Subtract 3 from -3 to get -6.

$$-\frac{3}{5}y\leq -6$$

Multiply both sides by -\frac{5}{3}, the reciprocal of -\frac{3}{5}. Since -\frac{3}{5} is negative, the inequality direction is changed.

$$y\geq -6\left(-\frac{5}{3}\right)$$

Express -6\left(-\frac{5}{3}\right) as a single fraction.

$$y\geq \frac{-6\left(-5\right)}{3}$$

Multiply -6 and -5 to get 30.

$$y\geq \frac{30}{3}$$

Divide 30 by 3 to get 10.

$$y\geq 10$$