Solve -3/5*{1-(2/3)^2}=

$$- \frac { 3 } { 5 } \times \{ 1 - ( \frac { 2 } { 3 } ) ^ { 2 } \} =$$

Evaluate

$$-\frac{1}{3}\approx -0.333333333$$

Solution Steps

Calculate \frac{2}{3} to the power of 2 and get \frac{4}{9}.

$$-\frac{3}{5}\left(1-\frac{4}{9}\right)$$

Convert 1 to fraction \frac{9}{9}.

$$-\frac{3}{5}\left(\frac{9}{9}-\frac{4}{9}\right)$$

Since \frac{9}{9} and \frac{4}{9} have the same denominator, subtract them by subtracting their numerators.

$$-\frac{3}{5}\times \frac{9-4}{9}$$

Subtract 4 from 9 to get 5.

$$-\frac{3}{5}\times \frac{5}{9}$$

Multiply -\frac{3}{5} times \frac{5}{9} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-3\times 5}{5\times 9}$$

Cancel out 5 in both numerator and denominator.

$$\frac{-3}{9}$$

Reduce the fraction \frac{-3}{9} to lowest terms by extracting and canceling out 3.

$$-\frac{1}{3}$$

Factor

$$-\frac{1}{3} = -0.3333333333333333$$