Solve -3/5^frac{1{3}}+3/4x=13/10

$$- \frac { 3 } { 5 } ^ { \frac { 1 } { 3 } } + \frac { 3 } { 4 } x = \frac { 13 } { 10 }$$

Solve for x

$$x = \frac{4 \sqrt[3]{3} \cdot 5 ^ {\frac{2}{3}} + 26}{15} \approx 2.85791022$$

Steps for Solving Linear Equation

Add \left(\frac{3}{5}\right)^{\frac{1}{3}} to both sides.

$$\frac{3}{4}x=\frac{13}{10}+\left(\frac{3}{5}\right)^{\frac{1}{3}}$$

Reorder the terms.

$$\frac{3}{4}x=\sqrt[3]{\frac{3}{5}}+\frac{13}{10}$$

Divide both sides of the equation by \frac{3}{4}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{3}{4}x}{\frac{3}{4}}=\frac{\frac{\sqrt[3]{3}\times 5^{\frac{2}{3}}}{5}+\frac{13}{10}}{\frac{3}{4}}$$

Dividing by \frac{3}{4} undoes the multiplication by \frac{3}{4}.

$$x=\frac{\frac{\sqrt[3]{3}\times 5^{\frac{2}{3}}}{5}+\frac{13}{10}}{\frac{3}{4}}$$

Divide \frac{5^{\frac{2}{3}}\sqrt[3]{3}}{5}+\frac{13}{10} by \frac{3}{4} by multiplying \frac{5^{\frac{2}{3}}\sqrt[3]{3}}{5}+\frac{13}{10} by the reciprocal of \frac{3}{4}.

$$x=\frac{4\sqrt[3]{3}\times 5^{\frac{2}{3}}+26}{15}$$