Solve -3/4-4(3/4)=-9(3/4)+3

$$- \frac { 3 } { 4 } - 4 ( \frac { 3 } { 4 } ) = - 9 ( \frac { 3 } { 4 } ) + 3$$

Verify

Solution Steps

Cancel out 4 and 4.

$$-\frac{3}{4}-3=-9\times \frac{3}{4}+3$$

Convert 3 to fraction \frac{12}{4}.

$$-\frac{3}{4}-\frac{12}{4}=-9\times \frac{3}{4}+3$$

Since -\frac{3}{4} and \frac{12}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-3-12}{4}=-9\times \frac{3}{4}+3$$

Subtract 12 from -3 to get -15.

$$-\frac{15}{4}=-9\times \frac{3}{4}+3$$

Express -9\times \frac{3}{4} as a single fraction.

$$-\frac{15}{4}=\frac{-9\times 3}{4}+3$$

Multiply -9 and 3 to get -27.

$$-\frac{15}{4}=\frac{-27}{4}+3$$

Fraction \frac{-27}{4} can be rewritten as -\frac{27}{4} by extracting the negative sign.

$$-\frac{15}{4}=-\frac{27}{4}+3$$

Convert 3 to fraction \frac{12}{4}.

$$-\frac{15}{4}=-\frac{27}{4}+\frac{12}{4}$$

Since -\frac{27}{4} and \frac{12}{4} have the same denominator, add them by adding their numerators.

$$-\frac{15}{4}=\frac{-27+12}{4}$$

Add -27 and 12 to get -15.

$$-\frac{15}{4}=-\frac{15}{4}$$

Compare -\frac{15}{4} and -\frac{15}{4}.

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