Solve -3/4*(-1,5-3/5)-1div3/2+5*0,18=

$$- \frac { 3 } { 4 } \cdot ( - 1,5 - \frac { 3 } { 5 } ) - 1 \div \frac { 3 } { 2 } + 5 \cdot 0,18 =$$

Evaluate

$$\frac{217}{120}\approx 1,808333333$$

Solution Steps

Convert decimal number -1,5 to fraction -\frac{15}{10}. Reduce the fraction -\frac{15}{10} to lowest terms by extracting and canceling out 5.

$$-\frac{3}{4}\left(-\frac{3}{2}-\frac{3}{5}\right)-\frac{1}{\frac{3}{2}}+5\times 0,18$$

Least common multiple of 2 and 5 is 10. Convert -\frac{3}{2} and \frac{3}{5} to fractions with denominator 10.

$$-\frac{3}{4}\left(-\frac{15}{10}-\frac{6}{10}\right)-\frac{1}{\frac{3}{2}}+5\times 0,18$$

Since -\frac{15}{10} and \frac{6}{10} have the same denominator, subtract them by subtracting their numerators.

$$-\frac{3}{4}\times \frac{-15-6}{10}-\frac{1}{\frac{3}{2}}+5\times 0,18$$

Subtract 6 from -15 to get -21.

$$-\frac{3}{4}\left(-\frac{21}{10}\right)-\frac{1}{\frac{3}{2}}+5\times 0,18$$

Multiply -\frac{3}{4} times -\frac{21}{10} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-3\left(-21\right)}{4\times 10}-\frac{1}{\frac{3}{2}}+5\times 0,18$$

Do the multiplications in the fraction \frac{-3\left(-21\right)}{4\times 10}.

$$\frac{63}{40}-\frac{1}{\frac{3}{2}}+5\times 0,18$$

Divide 1 by \frac{3}{2} by multiplying 1 by the reciprocal of \frac{3}{2}.

$$\frac{63}{40}-1\times \frac{2}{3}+5\times 0,18$$

Multiply 1 and \frac{2}{3} to get \frac{2}{3}.

$$\frac{63}{40}-\frac{2}{3}+5\times 0,18$$

Least common multiple of 40 and 3 is 120. Convert \frac{63}{40} and \frac{2}{3} to fractions with denominator 120.

$$\frac{189}{120}-\frac{80}{120}+5\times 0,18$$

Since \frac{189}{120} and \frac{80}{120} have the same denominator, subtract them by subtracting their numerators.

$$\frac{189-80}{120}+5\times 0,18$$

Subtract 80 from 189 to get 109.

$$\frac{109}{120}+5\times 0,18$$

Multiply 5 and 0,18 to get 0,9.

$$\frac{109}{120}+0,9$$

Convert decimal number 0,9 to fraction \frac{9}{10}.

$$\frac{109}{120}+\frac{9}{10}$$

Least common multiple of 120 and 10 is 120. Convert \frac{109}{120} and \frac{9}{10} to fractions with denominator 120.

$$\frac{109}{120}+\frac{108}{120}$$

Since \frac{109}{120} and \frac{108}{120} have the same denominator, add them by adding their numerators.

$$\frac{109+108}{120}$$

Add 109 and 108 to get 217.

$$\frac{217}{120}$$

Factor

$$\frac{7 \cdot 31}{3 \cdot 5 \cdot 2 ^ {3}} = 1\frac{97}{120} = 1.8083333333333333$$