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Solve for a_75
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-\frac{3}{4}+9xa_{75}=0
Multiply 0 and 5 to get 0.
9xa_{75}=\frac{3}{4}
Add \frac{3}{4} to both sides. Anything plus zero gives itself.
\frac{9xa_{75}}{9x}=\frac{\frac{3}{4}}{9x}
Divide both sides by 9x.
a_{75}=\frac{\frac{3}{4}}{9x}
Dividing by 9x undoes the multiplication by 9x.
a_{75}=\frac{1}{12x}
Divide \frac{3}{4} by 9x.
-\frac{3}{4}+9xa_{75}=0
Multiply 0 and 5 to get 0.
9xa_{75}=\frac{3}{4}
Add \frac{3}{4} to both sides. Anything plus zero gives itself.
9a_{75}x=\frac{3}{4}
The equation is in standard form.
\frac{9a_{75}x}{9a_{75}}=\frac{\frac{3}{4}}{9a_{75}}
Divide both sides by 9a_{75}.
x=\frac{\frac{3}{4}}{9a_{75}}
Dividing by 9a_{75} undoes the multiplication by 9a_{75}.
x=\frac{1}{12a_{75}}
Divide \frac{3}{4} by 9a_{75}.